C(n)=1.75n^2-n+33

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Solution for C(n)=1.75n^2-n+33 equation: 



(C)=1.75C^2-C+33

We move all terms to the left:

(C)-(1.75C^2-C+33)=0

We get rid of parentheses

-1.75C^2+C+C-33=0

We add all the numbers together, and all the variables

-1.75C^2+2C-33=0

a = -1.75; b = 2; c = -33;
Δ = b2-4ac
Δ = 22-4·(-1.75)·(-33)
Δ = -227
Delta is less than zero, so there is no solution for the equation

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